-3n^2+147=0

Solution for -3n^2+147=0 equation:

-3n^2+147=0

a = -3; b = 0; c = +147;
Δ = b2-4ac
Δ = 02-4·(-3)·147
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*-3}=\frac{-42}{-6}
=+7
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*-3}=\frac{42}{-6}
=-7
$